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Contest 4: A Cleverly-Titled Birthday Contest

On May 26, 2011, I will turn 24 years old. As has been traditional for the past several years, I will celebrate this event by adding new Nikoli puzzle books to my collection, a tradition which always gives me a bit of a rush. One tradition I will not engage in, though, is the singing of a particular song (yeah, you know the one). What song would I prefer to hear instead? Read on, and you could find out. . .

How to enter:
This contest consists of a single puzzle (as opposed to the four puzzles that my contests usually have – a shocking change of pace, I know). To participate in the contest, simply send the final answer in an e-mail to glmathgrant[at]gmail[dot]com. Only one entry is allowed per person, but you may change your entry at any time before the deadline, 11:59 PM (Central time) on May 25, 2011. The winners will be announced on my birthday, May 26, 2011.

How to win:
After the deadline has passed, four winners will be randomly selected from amongst the people who submitted the correct answer. (If fewer than four people submit the correct answer, then all of them will be winners.)

I'm not telling you what the prizes are. Gwa ha ha! I will only say that their monetary worth will surely not be as great as their worth as souvenirs of having celebrated my birthday. :)

By entering the contest, you agree to the following terms:
a) You agree not to discuss your entry with any other entrants or potential entrants until the contest is over.
b) You agree to provide me with a mailing address in the event that you win. (In return, I agree not to use your mailing address for any malicious purposes, such as sending junk mail or other undesired things.)
c) You agree to wait patiently for your prize to arrive, without moaning or kvetching, especially if you don't live in the continental United States, since it takes longer for things to ship from Texas to other countries, or to Alaska or Hawaii.

Now that you're done reading all that, here is the one-part contest puzzle. Good luck! :)

Only Part: Polyominous

Solve the Polyominous puzzle below (rules of Polyominous):
Transfer the units digits of the numbers in the lettered cells to the corresponding boxes in the URL beneath the images. (For example, if the cell with the letter a has a 2 or a 12, then box a in the URL will have a 2.) This URL will lead to a page on AllMusic; the song on this page was the inspiration for this contest.

For the final answer, you may submit either the URL obtained from solving the above puzzle, or the title of the song obtained from said URL. Send your answer to glmathgrant[at]gmail[dot]com to enter A Cleverly-Titled Birthday Contest.

Edit: I reserve the right to accept "close enough" answers at my discretion; I will consider the full URL, the URL without http:// and/or www., just the "t#######" part of the URL, or even just the seven-digit number by itself as correct, as well as minor misspellings of the title. However, URL's with two digits transposed or a single wrong digit, as well as completely wrong titles, will not be counted as correct.

If you submit both a URL and a title, and I notice that they don't match up, I will notify you of this. If you don't change your answer before the deadline, I will ignore the title and just check the URL (so if your URL is correct and your song title is preposterously wrong, your answer will be counted as correct).


linked_puffbird said...

Thank you for another fine puzzle, and happy birthday. I hope you realize the risk you are taking of receiving many strange songs with people's submissions!

Anurag Sahay said...

What a way to spend a sunday afternoon.It solves very lgically.I liked the way the bottom-right quadrant worked out.

Leo said...

Happy Birthday and thanks for the puzzle! I love how the 11 in the lower left turned out! I printed this one out and it kept me company while waiting to renew my driver's license. :)

Anonymous said...

A nice riddle, thanks, too!
Only field a (and one other field) seems to have two possibilities; also 1 seems to be possible at a.

Grant Fikes said...

Anonymous: This puzzle should only have one solution. If it didn't, I'm sure I would have been flooded with complaints by now from the 56 people who entered the contest. See this post for the results of the contest and the answer to the puzzle.

Not only is 1 possible at a, but 1 is the only number possible at a. If a were 7, then the cell below it would have a 1, yielding two adjacent regions of the same area, which is forbidden.

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